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475 lines
16 KiB
475 lines
16 KiB
/* |
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* Copyright (C) 2016 Intel Corporation. All rights reserved. |
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* |
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* This file is free software: you can redistribute it and/or modify it |
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* under the terms of the GNU General Public License as published by the |
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* Free Software Foundation, either version 3 of the License, or |
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* (at your option) any later version. |
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* |
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* This file is distributed in the hope that it will be useful, but |
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* WITHOUT ANY WARRANTY; without even the implied warranty of |
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. |
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* See the GNU General Public License for more details. |
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* |
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* You should have received a copy of the GNU General Public License along |
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* with this program. If not, see <http://www.gnu.org/licenses/>. |
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*/ |
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/* |
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* This comment section explains the basic idea behind the implementation. |
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* |
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* Vectors difference notation |
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* =========================== |
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* Let v and w be vectors. For readability purposes, unless explicitly |
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* otherwise noted, the notation vw will be used to represent w - v. |
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* |
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* Relationship between a vector and a triangle in 3d space |
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* ======================================================== |
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* Vector in the area of a triangle |
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* -------------------------------- |
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* Let T = (a, b, c) be a triangle, where a, b and c are also vectors and |
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* linearly independent. A vector inside that triangle can be written as one of |
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* its vertices plus the sum of the positively scaled vectors from that vertex |
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* to the other ones. Taking a as the first vertex, a vector p in the area |
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* formed by T can be written as: |
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* |
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* p = a + w_ab * ab + w_ac * ac |
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* |
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* It's fairly easy to see that if p is in the area formed by T, then w_ab >= 0 |
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* and w_ac >= 0. That vector p can also be written as: |
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* |
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* p = b + w_ba * ba + w_bc * bc |
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* |
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* It's easy to check that the triangle formed by (a + w_ab * ab, b + w_ba * |
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* ba, p) is similar to T and, with the correct algebraic manipulations, we can |
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* come to the conclusion that: |
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* |
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* w_ba = 1 - w_ab - w_ac |
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* |
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* Since we know that w_ba >= 0, then w_ab + w_ac <= 1. Thus: |
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* |
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* ---------------------------------------------------------- |
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* | p = a + w_ab * ab + w_ac * ac is in the area of T iff: | |
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* | w_ab >= 0 and w_ac >= 0 and w_ab + w_ac <= 1 | |
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* ---------------------------------------------------------- |
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* |
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* Proving backwards shouldn't be difficult. |
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* |
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* Vector p can also be written as: |
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* |
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* p = (1 - w_ab - w_ba) * a + w_ab * b + w_ba * c |
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* |
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* |
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* Vector that crosses a triangle |
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* ------------------------------ |
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* Let T be the same triangle discussed above and let v be a vector such that: |
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* |
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* v = x * a + y * b + z * c |
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* where x >= 0, y >= 0, z >= 0, and x + y + z > 0. |
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* |
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* It's geometrically easy to see that v crosses the triangle T. But that can |
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* also be verified analytically. |
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* |
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* The vector v crosses the triangle T iff there's a positive alpha such that |
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* alpha * v is in the area formed by T, so we need to prove that such value |
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* exists. To find alpha, we solve the equation alpha * v = p, which will lead |
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* us to the system, for the variables alpha, w_ab and w_ac: |
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* |
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* alpha * x = 1 - w_ab - w_ac |
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* alpha * y = w_ab |
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* alpha * z = w_ac, |
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* where w_ab >= 0 and w_ac >= 0 and w_ab + w_ac <= 1 |
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* |
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* That will lead to alpha = 1 / (x + y + z), w_ab = y / (x + y + b) and |
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* w_ac = z / (x + y + z) and the following holds: |
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* - alpha does exist because x + y + z > 0. |
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* - w_ab >= 0 and w_ac >= 0 because y >= 0 and z >= 0 and x + y + z > 0. |
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* - 0 <= 1 - w_ab - w_ac <= 1 because 0 <= (y + z) / (x + y + z) <= 1. |
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* |
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* Thus: |
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* |
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* ---------------------------------------------------------- |
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* | v = x * a + y * b + z * c crosses T = (a, b, c), where | |
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* | a, b and c are linearly independent, iff: | |
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* | x >= 0, y >= 0, z >= 0 and x + y + z > 0 | |
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* ---------------------------------------------------------- |
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* |
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* Moreover: |
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* - if one of the coefficients is zero, then v crosses the edge formed by the |
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* vertices multiplied by the non-zero coefficients. |
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* - if two of the coefficients are zero, then v crosses the vertex multiplied |
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* by the non-zero coefficient. |
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*/ |
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#include <assert.h> |
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#include "AP_GeodesicGrid.h" |
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/* This was generated with |
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* libraries/AP_Math/tools/geodesic_grid/geodesic_grid.py */ |
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const struct AP_GeodesicGrid::neighbor_umbrella |
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AP_GeodesicGrid::_neighbor_umbrellas[3]{ |
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{{ 9, 8, 7, 12, 14}, 1, 2, 0, 0, 2}, |
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{{ 1, 2, 4, 5, 3}, 0, 0, 2, 2, 0}, |
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{{16, 15, 13, 18, 17}, 2, 2, 0, 2, 1}, |
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}; |
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/* This was generated with |
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* libraries/AP_Math/tools/geodesic_grid/geodesic_grid.py */ |
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const Matrix3f AP_GeodesicGrid::_inverses[10]{ |
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{{-0.309017f, 0.500000f, 0.190983f}, |
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{ 0.000000f, 0.000000f, -0.618034f}, |
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{-0.309017f, -0.500000f, 0.190983f}}, |
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{{-0.190983f, 0.309017f, -0.500000f}, |
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{-0.500000f, -0.190983f, 0.309017f}, |
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{ 0.309017f, -0.500000f, -0.190983f}}, |
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{{-0.618034f, 0.000000f, 0.000000f}, |
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{ 0.190983f, -0.309017f, -0.500000f}, |
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{ 0.190983f, -0.309017f, 0.500000f}}, |
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{{-0.500000f, 0.190983f, -0.309017f}, |
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{ 0.000000f, -0.618034f, 0.000000f}, |
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{ 0.500000f, 0.190983f, -0.309017f}}, |
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{{-0.190983f, -0.309017f, -0.500000f}, |
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{-0.190983f, -0.309017f, 0.500000f}, |
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{ 0.618034f, 0.000000f, 0.000000f}}, |
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{{-0.309017f, -0.500000f, -0.190983f}, |
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{ 0.190983f, 0.309017f, -0.500000f}, |
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{ 0.500000f, -0.190983f, 0.309017f}}, |
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{{ 0.309017f, -0.500000f, 0.190983f}, |
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{ 0.000000f, 0.000000f, -0.618034f}, |
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{ 0.309017f, 0.500000f, 0.190983f}}, |
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{{ 0.190983f, -0.309017f, -0.500000f}, |
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{ 0.500000f, 0.190983f, 0.309017f}, |
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{-0.309017f, 0.500000f, -0.190983f}}, |
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{{ 0.500000f, -0.190983f, -0.309017f}, |
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{ 0.000000f, 0.618034f, 0.000000f}, |
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{-0.500000f, -0.190983f, -0.309017f}}, |
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{{ 0.309017f, 0.500000f, -0.190983f}, |
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{-0.500000f, 0.190983f, 0.309017f}, |
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{-0.190983f, -0.309017f, -0.500000f}}, |
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}; |
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/* This was generated with |
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* libraries/AP_Math/tools/geodesic_grid/geodesic_grid.py */ |
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const Matrix3f AP_GeodesicGrid::_mid_inverses[10]{ |
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{{-0.000000f, 1.000000f, -0.618034f}, |
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{ 0.000000f, -1.000000f, -0.618034f}, |
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{-0.618034f, 0.000000f, 1.000000f}}, |
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{{-1.000000f, 0.618034f, -0.000000f}, |
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{-0.000000f, -1.000000f, 0.618034f}, |
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{ 0.618034f, -0.000000f, -1.000000f}}, |
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{{-0.618034f, -0.000000f, -1.000000f}, |
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{ 1.000000f, -0.618034f, -0.000000f}, |
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{-0.618034f, 0.000000f, 1.000000f}}, |
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{{-1.000000f, -0.618034f, -0.000000f}, |
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{ 1.000000f, -0.618034f, 0.000000f}, |
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{-0.000000f, 1.000000f, -0.618034f}}, |
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{{-1.000000f, -0.618034f, 0.000000f}, |
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{ 0.618034f, 0.000000f, 1.000000f}, |
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{ 0.618034f, 0.000000f, -1.000000f}}, |
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{{-0.618034f, -0.000000f, -1.000000f}, |
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{ 1.000000f, 0.618034f, -0.000000f}, |
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{ 0.000000f, -1.000000f, 0.618034f}}, |
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{{ 0.000000f, -1.000000f, -0.618034f}, |
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{ 0.000000f, 1.000000f, -0.618034f}, |
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{ 0.618034f, -0.000000f, 1.000000f}}, |
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{{ 1.000000f, -0.618034f, -0.000000f}, |
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{ 0.000000f, 1.000000f, 0.618034f}, |
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{-0.618034f, 0.000000f, -1.000000f}}, |
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{{ 1.000000f, 0.618034f, -0.000000f}, |
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{-1.000000f, 0.618034f, 0.000000f}, |
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{ 0.000000f, -1.000000f, -0.618034f}}, |
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{{-0.000000f, 1.000000f, 0.618034f}, |
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{-1.000000f, -0.618034f, -0.000000f}, |
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{ 0.618034f, 0.000000f, -1.000000f}}, |
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}; |
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int AP_GeodesicGrid::section(const Vector3f &v, bool inclusive) |
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{ |
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int i = _triangle_index(v, inclusive); |
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if (i < 0) { |
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return -1; |
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} |
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int j = _subtriangle_index(i, v, inclusive); |
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if (j < 0) { |
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return -1; |
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} |
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return 4 * i + j; |
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} |
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int AP_GeodesicGrid::_neighbor_umbrella_component(int idx, int comp_idx) |
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{ |
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if (idx < 3) { |
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return _neighbor_umbrellas[idx].components[comp_idx]; |
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} |
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return (_neighbor_umbrellas[idx % 3].components[comp_idx] + 10) % 20; |
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} |
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int AP_GeodesicGrid::_from_neighbor_umbrella(int idx, |
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const Vector3f &v, |
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const Vector3f &u, |
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bool inclusive) |
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{ |
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/* The following comparisons between the umbrella's first and second |
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* vertices' coefficients work for this algorithm because all vertices' |
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* vectors are of the same length. */ |
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if (is_equal(u.x, u.y)) { |
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/* If the coefficients of the first and second vertices are equal, then |
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* v crosses the first component or the edge formed by the umbrella's |
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* pivot and forth vertex. */ |
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int comp = _neighbor_umbrella_component(idx, 0); |
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auto w = _inverses[comp % 10] * v; |
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if (comp > 9) { |
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w = -w; |
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} |
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float x0 = w[_neighbor_umbrellas[idx % 3].v0_c0]; |
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if (is_zero(x0)) { |
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if (!inclusive) { |
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return -1; |
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} |
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return comp; |
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} else if (x0 < 0) { |
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if (!inclusive) { |
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return -1; |
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} |
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return _neighbor_umbrella_component(idx, u.x < u.y ? 3 : 2); |
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} |
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return comp; |
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} |
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if (u.y > u.x) { |
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/* If the coefficient of the second vertex is greater than the first |
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* one's, then v crosses the first, second or third component. */ |
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int comp = _neighbor_umbrella_component(idx, 1); |
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auto w = _inverses[comp % 10] * v; |
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if (comp > 9) { |
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w = -w; |
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} |
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float x1 = w[_neighbor_umbrellas[idx % 3].v1_c1]; |
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float x2 = w[_neighbor_umbrellas[idx % 3].v2_c1]; |
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if (is_zero(x1)) { |
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if (!inclusive) { |
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return -1; |
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} |
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return _neighbor_umbrella_component(idx, x1 < 0 ? 2 : 1); |
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} else if (x1 < 0) { |
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return _neighbor_umbrella_component(idx, 2); |
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} |
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if (is_zero(x2)) { |
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if (!inclusive) { |
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return -1; |
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} |
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return _neighbor_umbrella_component(idx, x2 > 0 ? 1 : 0); |
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} else if (x2 < 0) { |
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return _neighbor_umbrella_component(idx, 0); |
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} |
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return comp; |
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} else { |
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/* If the coefficient of the second vertex is lesser than the first |
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* one's, then v crosses the first, fourth or fifth component. */ |
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int comp = _neighbor_umbrella_component(idx, 4); |
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auto w = _inverses[comp % 10] * v; |
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if (comp > 9) { |
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w = -w; |
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} |
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float x4 = w[_neighbor_umbrellas[idx % 3].v4_c4]; |
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float x0 = w[_neighbor_umbrellas[idx % 3].v0_c4]; |
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if (is_zero(x4)) { |
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if (!inclusive) { |
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return -1; |
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} |
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return _neighbor_umbrella_component(idx, x4 < 0 ? 0 : 4); |
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} else if (x4 < 0) { |
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return _neighbor_umbrella_component(idx, 0); |
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} |
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if (is_zero(x0)) { |
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if (!inclusive) { |
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return -1; |
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} |
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return _neighbor_umbrella_component(idx, x0 > 0 ? 4 : 3); |
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} else if (x0 < 0) { |
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return _neighbor_umbrella_component(idx, 3); |
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} |
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return comp; |
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} |
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} |
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int AP_GeodesicGrid::_triangle_index(const Vector3f &v, bool inclusive) |
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{ |
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/* w holds the coordinates of v with respect to the basis comprised by the |
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* vectors of T_i */ |
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auto w = _inverses[0] * v; |
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int zero_count = 0; |
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int balance = 0; |
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int umbrella = -1; |
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if (is_zero(w.x)) { |
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zero_count++; |
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} else if (w.x > 0) { |
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balance++; |
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} else { |
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balance--; |
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} |
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if (is_zero(w.y)) { |
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zero_count++; |
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} else if (w.y > 0) { |
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balance++; |
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} else { |
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balance--; |
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} |
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if (is_zero(w.z)) { |
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zero_count++; |
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} else if (w.z > 0) { |
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balance++; |
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} else { |
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balance--; |
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} |
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switch (balance) { |
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case 3: |
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/* All coefficients are positive, thus return the first triangle. */ |
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return 0; |
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case -3: |
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/* All coefficients are negative, which means that the coefficients for |
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* -w are positive, thus return the first triangle's opposite. */ |
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return 10; |
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case 2: |
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/* Two coefficients are positive and one is zero, thus v crosses one of |
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* the edges of the first triangle. */ |
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return inclusive ? 0 : -1; |
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case -2: |
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/* Analogous to the previous case, but for the opposite of the first |
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* triangle. */ |
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return inclusive ? 10 : -1; |
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case 1: |
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/* There are two possible cases when balance is 1: |
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* |
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* 1) Two coefficients are zero, which means v crosses one of the |
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* vertices of the first triangle. |
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* |
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* 2) Two coefficients are positive and one is negative. Let a and b be |
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* vertices with positive coefficients and c the one with the negative |
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* coefficient. That means that v crosses the triangle formed by a, b |
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* and -c. The vector -c happens to be the 3-th vertex, with respect to |
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* (a, b), of the first triangle's neighbor umbrella with respect to a |
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* and b. Thus, v crosses one of the components of that umbrella. */ |
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if (zero_count == 2) { |
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return inclusive ? 0 : -1; |
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} |
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if (!is_zero(w.x) && w.x < 0) { |
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umbrella = 1; |
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} else if (!is_zero(w.y) && w.y < 0) { |
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umbrella = 2; |
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} else { |
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umbrella = 0; |
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} |
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break; |
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case -1: |
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/* Analogous to the previous case, but for the opposite of the first |
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* triangle. */ |
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if (zero_count == 2) { |
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return inclusive ? 10 : -1; |
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} |
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if (!is_zero(w.x) && w.x > 0) { |
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umbrella = 4; |
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} else if (!is_zero(w.y) && w.y > 0) { |
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umbrella = 5; |
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} else { |
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umbrella = 3; |
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} |
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w = -w; |
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break; |
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case 0: |
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/* There are two possible cases when balance is 1: |
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* |
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* 1) The vector v is the null vector, which doesn't cross any section. |
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* |
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* 2) One coefficient is zero, another is positive and yet another is |
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* negative. Let a, b and c be the respective vertices for those |
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* coefficients, then the statements in case (2) for when balance is 1 |
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* are also valid here. |
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*/ |
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if (zero_count == 3) { |
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return -1; |
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} |
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if (!is_zero(w.x) && w.x < 0) { |
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umbrella = 1; |
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} else if (!is_zero(w.y) && w.y < 0) { |
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umbrella = 2; |
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} else { |
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umbrella = 0; |
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} |
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break; |
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} |
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switch (umbrella % 3) { |
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case 0: |
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w.z = -w.z; |
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break; |
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case 1: |
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w = {w.y, w.z, -w.x}; |
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break; |
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case 2: |
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w = {w.z, w.x, -w.y}; |
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break; |
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} |
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return _from_neighbor_umbrella(umbrella, v, w, inclusive); |
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} |
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int AP_GeodesicGrid::_subtriangle_index(const unsigned int triangle_index, |
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const Vector3f &v, |
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bool inclusive) |
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{ |
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/* w holds the coordinates of v with respect to the basis comprised by the |
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* vectors of the middle triangle of T_i where i is triangle_index */ |
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auto w = _mid_inverses[triangle_index % 10] * v; |
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if (triangle_index > 9) { |
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w = -w; |
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} |
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if ((is_zero(w.x) || is_zero(w.y) || is_zero(w.z)) && !inclusive) { |
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return -1; |
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} |
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/* At this point, we know that v crosses the icosahedron triangle pointed |
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* by triangle_index. Thus, we can geometrically see that if v doesn't |
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* cross its middle triangle, then one of the coefficients will be negative |
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* and the other ones positive. Let a and b be the non-negative |
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* coefficients and c the negative one. In that case, v will cross the |
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* triangle with vertices (a, b, -c). Since we know that v crosses the |
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* icosahedron triangle and the only sub-triangle that contains the set of |
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* points (seen as vectors) that cross the triangle (a, b, -c) is the |
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* middle triangle's neighbor with respect to a and b, then that |
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* sub-triangle is the one crossed by v. */ |
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if (!is_zero(w.x) && w.x < 0) { |
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return 3; |
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} |
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if (!is_zero(w.y) && w.y < 0) { |
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return 1; |
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} |
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if (!is_zero(w.z) && w.z < 0) { |
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return 2; |
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} |
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/* If x >= 0 and y >= 0 and z >= 0, then v crosses the middle triangle. */ |
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return 0; |
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}
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